[tex] \frac{ \sqrt{2} }{ \sqrt{5} - \sqrt{3} } = [/tex]
[tex] \frac{ \sqrt{2} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } = [/tex]
[tex] \frac{ \sqrt{2} ( \sqrt{5 } + \sqrt{3} ) }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } = [/tex]
[tex] \frac{ \sqrt{2}( \sqrt{5}+ \sqrt{3} )}{5 - 3} = [/tex]
[tex] \frac{ \sqrt{2 } \sqrt{5} + \sqrt{2} \sqrt{3} }{2} = [/tex]
[tex] \frac{ \sqrt{10} + \sqrt{6} }{2} = [/tex]
[tex] \frac{ \sqrt{6} + \sqrt{10} }{2} [/tex]
Materi : Bentuk Akar dan Pangkat
√2/( √5 - √3 )
= √2( √5 + √3 )/( √5 - √3 )( √5 + √3 )
= ( √10 + √6 )/( [√5]² - [√3]² )
= ( √10 + √6 )/( 5 - 3 )
= ½( √10 + √6 )
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
